函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:mm\slub.c Create Date:2022-07-27 17:23:21
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称：__ksize

函数原型：size_t __ksize(const void *object)

返回类型：size_t

参数：

类型参数名称
const void *object
3922  如果此条件成立可能性小(为编译器优化)(object == ZERO_SIZE_PTR will be returned for zero sized kmalloc requests.* Dereferencing ZERO_SIZE_PTR will lead to a distinct access fault.* ZERO_SIZE_PTR can be passed to kfree though in the same way that NULL can.* Both make kfree a no-op.)则返回:0
3925  page等于virt_to_head_page(object)
3927  如果此条件成立可能性小(为编译器优化)(!PageSlab(page))则
3928  WARN_ON(!PageCompound(page))
3929  返回:Returns the number of bytes in this potentially compound page.
3932  返回:slab_ksize(用于SLUB分配器，指向slab的指针)
调用者
名称描述
ksizeksize - get the actual amount of memory allocated for a given object*@objp: Pointer to the object* kmalloc may internally round up allocations and return more memory* than requested. ksize() can be used to determine the actual amount of* memory allocated