函数逻辑报告 |
Source Code:include\linux\mm.h |
Create Date:2022-07-27 06:44:41 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Returns the number of bytes in this potentially compound page.
函数原型:static inline unsigned long page_size(struct page *page)
返回类型:unsigned long
参数:
类型 | 参数 | 名称 |
---|---|---|
struct page * | page |
797 | 返回:PAGE_SIZE左移compound_order(page)位 |
名称 | 描述 |
---|---|
page_copy_sane | |
kobjsize | Return the total memory allocated for this pointer, not* just what the caller asked for.* Doesn't have to be accurate, i.e. may have races. |
page_vma_mapped_walk | page_vma_mapped_walk - check if @pvmw->page is mapped in @pvmw->vma at*@pvmw->address*@pvmw: pointer to struct page_vma_mapped_walk. page, vma, address and flags* must be set. pmd, pte and ptl must be NULL.* Returns true if the page is mapped in the vma |
page_mkclean_one | |
try_to_unmap_one | @arg: enum ttu_flags will be passed to this argument |
madvise_inject_error | Error injection support for memory error handling. |
__ksize | an't use ksize for kmem_cache_alloc memory, only kmalloc |
__ksize | |
kasan_poison_slab | |
kasan_kmalloc_large | |
kasan_poison_kfree | |
io_uring_validate_mmap_request | |
page_hstate |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |