函数逻辑报告

函数名称：map_parse_user - convert an ASCII hex string in a user buffer into a bitmap*@ubuf: pointer to user buffer containing string.*@ulen: buffer size in bytes. If string is smaller than this* then it must be terminated with a \0.

函数原型：int bitmap_parse_user(const char __user *ubuf, unsigned int ulen, unsigned long *maskp, int nmaskbits)

返回类型：int

参数：