__bitmap_parse

函数名称：__bitmap_parse - convert an ASCII hex string into a bitmap

函数原型：int __bitmap_parse(const char *buf, unsigned int buflen, int is_user, unsigned long *maskp, int nmaskbits)

返回类型：int

参数：

类型	参数	名称
const char *	buf
unsigned int	buflen
int	is_user
unsigned long *	maskp
int	nmaskbits

400

chunk等于0

401

ndigits等于totaldigits

404

当buflen 循环

405

old_c等于c

406

如果is_user则

407

如果__get_user - Get a simple variable from user space, with less checking(c, ubuf++)则返回:负EFAULT

410

否则c等于buf自加

412

buflen自减

413

如果Note: isspace() must return false for %NUL-terminator (c)则继续下一循环

421

如果totaldigits且c且Note: isspace() must return false for %NUL-terminator (old_c)则返回:负EINVAL

425

如果c恒等于'\0'或c恒等于','则退出

428

如果非isxdigit(c)则返回:负EINVAL

436

如果chunk按位与1UL左移Bitmap printing & parsing functions: first version by Nadia Yvette Chambers,* second version by Paul Jackson, third by Joe Korty.减4位的值减1的差的反则返回:负EOVERFLOW

439

chunk等于chunk左移4位按位或十六进制数字转换为实数

440

totaldigits自加

442

如果ndigits恒等于totaldigits则返回:负EINVAL

444

如果nchunks恒等于0且chunk恒等于0则继续下一循环

447

__bitmap_shift_left - logical left shift of the bits in a bitmap*@dst : destination bitmap*@src : source bitmap*@shift : shift by this many bits*@nbits : bitmap size, in bits* Shifting left (multiplying) means moving bits in the LS -> MS* direction

448

maskp或等于chunk

449

nchunks自加

450

nbits加等于如果nchunks恒等于1则nbits_to_hold_value(chunk)否则Bitmap printing & parsing functions: first version by Nadia Yvette Chambers,* second version by Paul Jackson, third by Joe Korty.

451

如果nbits大于nmaskbits则返回:负EOVERFLOW

**调用者**
名称	描述
bitmap_parse_user	map_parse_user - convert an ASCII hex string in a user buffer into a bitmap@ubuf: pointer to user buffer containing string.@ulen: buffer size in bytes. If string is smaller than this* then it must be terminated with a \0.
bitmap_parse

函数逻辑报告