函数逻辑报告 |
Source Code:kernel\locking\rtmutex.c |
Create Date:2022-07-27 10:52:44 |
| Last Modify:2020-03-17 14:26:38 | Copyright©Brick |
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函数名称：rt_mutex_futex_unlock
函数原型：void __sched rt_mutex_futex_unlock(struct rt_mutex *lock)
返回类型：void
参数：
| 类型 | 参数 | 名称 |
|---|---|---|
| struct rt_mutex * | lock |
| 1641 | raw_spin_lock_irqsave( & 保护自旋锁, flags) |
| 1642 | postunlock等于Futex variant, that since futex variants do not use the fast-path, can be* simple and will not need to retry. |
| 1643 | raw_spin_unlock_irqrestore( & 保护自旋锁, flags) |
| 名称 | 描述 |
|---|---|
| futex_lock_pi | Userspace tried a 0 -> TID atomic transition of the futex value* and failed. The kernel side here does the whole locking operation:* if there are waiters then it will block as a consequence of relying* on rt-mutexes, it does PI, etc |
| futex_wait_requeue_pi | ex_wait_requeue_pi() - Wait on uaddr and take uaddr2*@uaddr: the futex we initially wait on (non-pi)*@flags: futex flags (FLAGS_SHARED, FLAGS_CLOCKRT, etc |
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|---|---|
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