函数逻辑报告 |
Source Code:kernel\locking\rtmutex.c |
Create Date:2022-07-27 10:52:44 |
| Last Modify:2020-03-17 14:26:38 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Futex variant, that since futex variants do not use the fast-path, can be* simple and will not need to retry.
函数原型:bool __sched __rt_mutex_futex_unlock(struct rt_mutex *lock, struct wake_q_head *wake_q)
返回类型:bool
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct rt_mutex * | lock | |
| struct wake_q_head * | wake_q |
| 1615 | lockdep_assert_held( & 保护自旋锁) |
| 1617 | debug_rt_mutex_unlock(lock) |
| 1619 | 如果非rt_mutex_has_waiters(lock)则 |
| 1620 | 独占进程 = NULL |
| 1621 | 返回:false |
| 1632 | 返回:true |
| 名称 | 描述 |
|---|---|
| rt_mutex_futex_unlock | |
| wake_futex_pi | Caller must hold a reference on @pi_state. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |