函数逻辑报告 |
Source Code:include\linux\fscrypt.h |
Create Date:2022-07-29 10:32:14 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:scrypt_prepare_symlink - prepare to create a possibly-encrypted symlink*@dir: directory in which the symlink is being created*@target: plaintext symlink target*@len: length of @target excluding null terminator*@max_len: space the filesystem has available
函数原型:static inline int fscrypt_prepare_symlink(struct inode *dir, const char *target, unsigned int len, unsigned int max_len, struct fscrypt_str *disk_link)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | dir | |
const char * | target | |
unsigned int | len | |
unsigned int | max_len | |
struct fscrypt_str * | disk_link |
705 | 如果IS_ENCRYPTED(dir)或fscrypt_dummy_context_enabled(dir)则返回:__fscrypt_prepare_symlink(dir, len, max_len, disk_link) |
710 | 如果len大于max_len则返回:负ENAMETOOLONG |
712 | 返回:0 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |