函数逻辑报告 |
Source Code:fs\crypto\hooks.c |
Create Date:2022-07-29 10:57:10 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:__fscrypt_prepare_symlink
函数原型:int __fscrypt_prepare_symlink(struct inode *dir, unsigned int len, unsigned int max_len, struct fscrypt_str *disk_link)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | dir | |
unsigned int | len | |
unsigned int | max_len | |
struct fscrypt_str * | disk_link |
143 | 如果非fscrypt_has_encryption_key(dir)则返回:负ENOKEY |
157 | 如果非fscrypt_fname_encrypted_size(dir, len, max_len - sizeof(structfscrypt_symlink_data), & len)则返回:负ENAMETOOLONG |
161 | len加等于sizeof(structfscrypt_symlink_data) |
163 | name = NULL |
164 | 返回:0 |
名称 | 描述 |
---|---|
fscrypt_prepare_symlink | scrypt_prepare_symlink - prepare to create a possibly-encrypted symlink*@dir: directory in which the symlink is being created*@target: plaintext symlink target*@len: length of @target excluding null terminator*@max_len: space the filesystem has available |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |