函数逻辑报告

函数名称：smack_unix_may_send - Smack access on UDS*@sock: one socket*@other: the other socket* Return 0 if a subject with the smack of sock could access* an object with the smack of other, otherwise an error code

函数原型：static int smack_unix_may_send(struct socket *sock, struct socket *other)

返回类型：int

参数：