函数逻辑报告 |
Source Code:security\security.c |
Create Date:2022-07-27 20:13:34 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:security_task_alloc
函数原型:int security_task_alloc(struct task_struct *task, unsigned long clone_flags)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct task_struct * | task | |
unsigned long | clone_flags |
1506 | rc等于lsm_task_alloc - allocate a composite task blob*@task: the task that needs a blob* Allocate the task blob for all the modules* Returns 0, or -ENOMEM if memory can't be allocated. |
1510 | rc等于call_int_hook(task_alloc, 0, task, clone_flags) |
1511 | 如果此条件成立可能性小(为编译器优化)(rc)则security_task_free(task) |
1513 | 返回:rc |
名称 | 描述 |
---|---|
copy_process | 创建进程 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |