函数逻辑报告 |
Source Code:security\keys\persistent.c |
Create Date:2022-07-27 20:00:39 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:Get the persistent keyring for a specific UID and link it to the nominated* keyring.
函数原型:static long key_get_persistent(struct user_namespace *ns, kuid_t uid, key_ref_t dest_ref)
返回类型:long
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct user_namespace * | ns | |
| kuid_t | uid | |
| key_ref_t | dest_ref |
| 84 | type等于key_type_keyring |
| 85 | description等于buf |
| 95 | 如果persistent_ref则转到:found |
| 102 | lock for writing |
| 103 | persistent_ref等于Create the persistent keyring for the specified user.* Called with the namespace's sem locked for writing. |
| 108 | 返回:错误 |
| 110 | found : |
| 112 | 如果ret恒等于0则 |
| 115 | 如果ret恒等于0则 |
| 122 | 返回:ret |
| 名称 | 描述 |
|---|---|
| keyctl_get_persistent | Get the persistent keyring for a specific UID and link it to the nominated* keyring. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |