函数逻辑报告 |
Source Code:security\commoncap.c |
Create Date:2022-07-27 20:10:35 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:1) Audit candidate if current->cap_effective is set* We do not bother to audit if 3 things are true:* 1) cap_effective has all caps* 2) we became root *OR* are were already root* 3) root is supposed to have all caps (SECURE_NOROOT)
函数原型:static inline bool nonroot_raised_pE(struct cred *new, const struct cred *old, kuid_t root, bool has_fcap)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct cred * | new | |
const struct cred * | old | |
kuid_t | root | |
bool | has_fcap |
780 | bool ret = false |
782 | 如果__cap_grew(effective, ambient, new)且非__cap_full(effective, new)且__is_eff(root, new)或__is_real(root, new)的值且root_privileged()的值或root_privileged()且__is_suid(root, new)且非__cap_full(effective, new)或非__is_setuid(new, old)且has_fcap且__cap_gained(permitted, new, old)或__cap_gained(ambient, new, old)的值则ret = true |
796 | 返回:ret |
名称 | 描述 |
---|---|
cap_bprm_set_creds | ap_bprm_set_creds - Set up the proposed credentials for execve().*@bprm: The execution parameters, including the proposed creds* Set up the proposed credentials for a new execution context being* constructed by execve() |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |