函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:mm\zbud.c Create Date:2022-07-27 18:00:35
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称:Returns the number of free chunks in a zbud page

函数原型:static int num_free_chunks(struct zbud_header *zhdr)

返回类型:int

参数:

类型参数名称
struct zbud_header *zhdr
292  返回:NCHUNKSfirst_chunkslast_chunks
调用者
名称描述
zbud_alloczbud_alloc() - allocates a region of a given size*@pool: zbud pool from which to allocate*@size: size in bytes of the desired allocation*@gfp: gfp flags used if the pool needs to grow*@handle: handle of the new allocation* This function will attempt to
zbud_freezbud_free() - frees the allocation associated with the given handle*@pool: pool in which the allocation resided*@handle: handle associated with the allocation returned by zbud_alloc()* In the case that the zbud page in which the allocation resides is
zbud_reclaim_pagezbud_reclaim_page() - evicts allocations from a pool page and frees it*@pool: pool from which a page will attempt to be evicted*@retries: number of pages on the LRU list for which eviction will* be attempted before failing* zbud reclaim is different from