slab_order

函数名称：Calculate the order of allocation given an slab object size.* The order of allocation has significant impact on performance and other* system components. Generally order 0 allocations should be preferred since

函数原型：static inline unsigned int slab_order(unsigned int size, unsigned int min_objects, unsigned int max_order, unsigned int fract_leftover)

返回类型：unsigned int

参数：

类型	参数	名称
unsigned int	size
unsigned int	min_objects
unsigned int	max_order
unsigned int	fract_leftover

3251

min_order等于Mininum / Maximum order of slab pages. This influences locking overhead* and slab fragmentation. A higher order reduces the number of partial slabs* and increases the number of allocations possible without having to* take the list_lock.

3254

如果order_objects(min_order, size)大于since page.objects is u15 则返回:get_order - Determine the allocation order of a memory size*@size: The size for which to get the order* Determine the allocation order of a particular sized block of memory减1

3257

以order小于等于max_order 循环

3260

slab_size等于PAGE_SIZE左移order位

3263

rem等于slab_size取模size

3265

如果rem小于等于slab_size除fract_leftover则退出

3269

返回:order

**调用者**
名称	描述
calculate_order

源代码转换工具开放的插件接口	X
支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告代码生成和批量转换代码

函数逻辑报告