函数逻辑报告 |
Source Code:mm\page_alloc.c |
Create Date:2022-07-27 16:35:52 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:oom_reserves_allowed
函数原型:static bool oom_reserves_allowed(struct task_struct *tsk)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct task_struct * | tsk |
4215 | 如果非tsk_is_oom_victim(tsk)则返回:false |
4222 | 如果非IS_ENABLED(CONFIG_FOO) evaluates to 1 if CONFIG_FOO is set to 'y' or 'm',* 0 otherwise.(CONFIG_MMU)且非test_thread_flag(s terminating due to OOM killer )则返回:false |
4225 | 返回:true |
名称 | 描述 |
---|---|
__gfp_pfmemalloc_flags | Distinguish requests which really need access to full memory* reserves from oom victims which can live with a portion of it |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |