函数逻辑报告 |
Source Code:mm\page_alloc.c |
Create Date:2022-07-27 16:34:41 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Do the hard work of removing an element from the buddy allocator.* Call me with the zone->lock already held.
函数原型:static __always_inline struct page *__rmqueue(struct zone *zone, unsigned int order, int migratetype, unsigned int alloc_flags)
返回类型:struct page
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct zone * | zone | |
| unsigned int | order | |
| int | migratetype | |
| unsigned int | alloc_flags |
| 2714 | retry : |
| 2715 | page等于Go through the free lists for the given migratetype and remove* the smallest available page from the freelists |
| 2716 | 如果此条件成立可能性小(为编译器优化)(!page)则 |
| 2717 | 如果migratetype恒等于MIGRATE_MOVABLE则page等于__rmqueue_cma_fallback(zone, order) |
| 2726 | 返回:page |
| 名称 | 描述 |
|---|---|
| rmqueue_bulk | Obtain a specified number of elements from the buddy allocator, all under* a single hold of the lock, for efficiency. Add them to the supplied list.* Returns the number of new pages which were placed at *list. |
| rmqueue | Allocate a page from the given zone. Use pcplists for order-0 allocations. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |