函数逻辑报告 |
Source Code:lib\xarray.c |
Create Date:2022-07-27 07:10:43 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:xas_get_mark() - Returns the state of this mark.*@xas: XArray operation state.*@mark: Mark number.* Return: true if the mark is set, false if the mark is clear or @xas* is in an error state.
函数原型:bool xas_get_mark(const struct xa_state *xas, xa_mark_t mark)
返回类型:bool
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| const struct xa_state * | xas | |
| xa_mark_t | mark |
| 855 | 如果非xa_node则返回:xa_marked() - Inquire whether any entry in this array has a mark set*@xa: Array*@mark: Mark value* Context: Any context.* Return: %true if any entry has this mark set. |
| 857 | 返回:node_get_mark(xa_node, xa_offset, mark) |
| 名称 | 描述 |
|---|---|
| xa_get_mark | xa_get_mark() - Inquire whether this mark is set on this entry.*@xa: XArray.*@index: Index of entry.*@mark: Mark number.* This function uses the RCU read lock, so the result may be out of date* by the time it returns |
| check_xa_mark_2 | |
| __dax_invalidate_entry | |
| dax_writeback_one |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |