函数逻辑报告 |
Source Code:lib\test_xarray.c |
Create Date:2022-07-27 07:31:35 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:We should always be able to store without allocating memory after* reserving a slot.
函数原型:static void check_align_2(struct xarray *xa, char *name)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct xarray * | xa | |
| char * | name |
| 1477 | XA_BUG_ON(xa, !xa_empty() - Determine if an array has any present entries.*@xa: XArray.* Context: Any context.* Return: %true if the array contains only NULL pointers.) |
| 1490 | XA_BUG_ON(xa, !xa_empty() - Determine if an array has any present entries.*@xa: XArray.* Context: Any context.* Return: %true if the array contains only NULL pointers.) |
| 名称 | 描述 |
|---|---|
| check_align |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |