函数逻辑报告

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Source Code:lib\parser.c Create Date:2022-07-27 07:16:21
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称:match_hex: - scan a hex representation of an integer from a substring_t*@s: substring_t to be scanned*@result: resulting integer on success* Description: Attempts to parse the &substring_t @s as a hexadecimal integer

函数原型:int match_hex(substring_t *s, int *result)

返回类型:int

参数:

类型参数名称
substring_t *s
int *result
234  返回:match_number: scan a number in the given base from a substring_t*@s: substring to be scanned*@result: resulting integer on success*@base: base to use when converting string* Description: Given a &substring_t and a base, attempts to parse the substring