函数逻辑报告 |
Source Code:lib\objagg.c |
Create Date:2022-07-27 08:22:29 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:objagg_obj_parent_assign
函数原型:static int objagg_obj_parent_assign(struct objagg *objagg, struct objagg_obj *objagg_obj, struct objagg_obj *parent, bool take_parent_ref)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct objagg * | objagg | |
struct objagg_obj * | objagg_obj | |
struct objagg_obj * | parent | |
bool | take_parent_ref |
170 | delta_priv等于delta_create(priv, obj, obj) |
179 | user delta private 等于delta_priv |
180 | 如果take_parent_ref则objagg_obj_ref_inc( if the object is nested, this * holds pointer to parent, otherwise NULL) |
182 | trace_objagg_obj_parent_assign(objagg, objagg_obj, parent, counts number of users of this object * including nested objects) |
185 | 返回:0 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |