函数逻辑报告 |
Source Code:lib\bitmap.c |
Create Date:2022-07-27 07:17:32 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:map_find_free_region - find a contiguous aligned mem region*@bitmap: array of unsigned longs corresponding to the bitmap*@bits: number of bits in the bitmap*@order: region size (log base 2 of number of bits) to find* Find a region of free (zero) bits in a
函数原型:int bitmap_find_free_region(unsigned long *bitmap, unsigned int bits, int order)
返回类型:int
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| unsigned long * | bitmap | |
| unsigned int | bits | |
| int | order |
| 1115 | 如果非__reg_op(bitmap, pos, order, REG_OP_ISFREE)则继续下一循环 |
| 1117 | __reg_op(bitmap, pos, order, REG_OP_ALLOC) |
| 1118 | 返回:pos |
| 1120 | 返回:负ENOMEM |
| 名称 | 描述 |
|---|---|
| __dma_alloc_from_coherent |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |