函数逻辑报告 |
Source Code:kernel\workqueue.c |
Create Date:2022-07-27 10:26:57 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:manage_workers - manage worker pool*@worker: self* Assume the manager role and manage the worker pool @worker belongs* to. At any given time, there can be only zero or one manager per* pool. The exclusion is handled automatically by this function.
函数原型:static bool manage_workers(struct worker *worker)
返回类型:bool
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct worker * | worker |
| 2127 | pool等于A: the associated pool |
| 2129 | 如果X: flags 按位与POOL_MANAGER_ACTIVE则返回:false |
| 2132 | X: flags 或等于POOL_MANAGER_ACTIVE |
| 2133 | L: purely informational 等于worker |
| 2137 | L: purely informational = NULL |
| 2138 | X: flags 与等于POOL_MANAGER_ACTIVE的反 |
| 2139 | wake_up( & wq_manager_wait) |
| 2140 | 返回:true |
| 名称 | 描述 |
|---|---|
| worker_thread |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |