函数逻辑报告 |
Source Code:kernel\workqueue.c |
Create Date:2022-07-27 10:24:00 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Do I need to keep working? Called from currently running workers.
函数原型:static bool keep_working(struct worker_pool *pool)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct worker_pool * | pool |
789 | 返回:非链表为空且atomic_read( & The current concurrency level. As it's likely to be accessed* from other CPUs during try_to_wake_up(), put it in a separate* cacheline.)小于等于1 |
名称 | 描述 |
---|---|
worker_thread |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |