函数逻辑报告 |
Source Code:kernel\user.c |
Create Date:2022-07-27 10:13:56 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:uid_hash_find
函数原型:static struct user_struct *uid_hash_find(kuid_t uid, struct hlist_head *hashent)
返回类型:struct user_struct
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| kuid_t | uid | |
| struct hlist_head * | hashent |
| 128 | 返回:user |
| 132 | 返回:NULL |
| 名称 | 描述 |
|---|---|
| find_user | Locate the user_struct for the passed UID. If found, take a ref on it. The* caller must undo that ref with free_uid().* If the user_struct could not be found, return NULL. |
| alloc_uid |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |