函数逻辑报告 |
Source Code:kernel\sched\topology.c |
Create Date:2022-07-27 10:43:20 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:Find the sched_domain_topology_level where all CPU capacities are visible* for all CPUs.
函数原型:static struct sched_domain_topology_level *asym_cpu_capacity_level(const struct cpumask *cpu_map)
返回类型:struct sched_domain_topology_level
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| const struct cpumask * | cpu_map |
| 1925 | asym_level等于0 |
| 1926 | bool asym = false |
| 1927 | struct sched_domain_topology_level * tl, * asym_tl = NULL |
| 1934 | 如果arch_scale_cpu_capacity(i)不等于cap则 |
| 1940 | 如果非asym则返回:NULL |
| 1949 | max_capacity等于arch_scale_cpu_capacity(i) |
| 1950 | tl_id等于0 |
| 1953 | 如果tl_id小于asym_level则转到:next_level |
| 1959 | capacity等于arch_scale_cpu_capacity(j) |
| 1961 | 如果capacity小于等于max_capacity则继续下一循环 |
| 1964 | max_capacity等于capacity |
| 1965 | asym_level等于tl_id |
| 1968 | next_level : |
| 1969 | tl_id自加 |
| 1973 | 返回:asym_tl |
| 名称 | 描述 |
|---|---|
| build_sched_domains | Build sched domains for a given set of CPUs and attach the sched domains* to the individual CPUs |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |