函数逻辑报告

函数名称：a1 = a0 * e + a * (1 - e)* a2 = a1 * e + a * (1 - e)* = (a0 * e + a * (1 - e)) * e + a * (1 - e)* = a0 * e^2 + a * (1 - e) * (1 + e)* a3 = a2 * e + a * (1 - e)* = (a0 * e^2 + a * (1 - e) * (1 + e)) * e + a * (1 - e)* = a0 * e^3 + a * (1 - e) * (1 + e +

函数原型：unsigned long calc_load_n(unsigned long load, unsigned long exp, unsigned long active, unsigned int n)

返回类型：unsigned long

参数：