函数逻辑报告 |
Source Code:kernel\sched\core.c |
Create Date:2022-07-27 10:36:25 |
Last Modify:2022-05-22 13:40:38 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:prepare_task
函数原型:static inline void prepare_task(struct task_struct *next)
返回类型:void
参数:
类型 | 参数 | 名称 |
---|---|---|
struct task_struct * | next |
NULL
名称 | 描述 |
---|---|
prepare_task_switch | prepare_task_switch - prepare to switch tasks*@rq: the runqueue preparing to switch*@prev: the current task that is being switched out*@next: the task we are going to switch to |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |