函数逻辑报告 |
Source Code:kernel\resource.c |
Create Date:2022-07-27 10:04:42 |
Last Modify:2022-05-22 11:14:39 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Return the conflict entry if you can't request it
函数原型:static struct resource *__request_resource(struct resource *root, struct resource *new)
返回类型:struct resource
参数:
类型 | 参数 | 名称 |
---|---|---|
struct resource * | root | |
struct resource * | new |
198 | 循环 |
209 | 返回:tmp |
名称 | 描述 |
---|---|
request_resource_conflict | quest_resource_conflict - request and reserve an I/O or memory resource*@root: root resource descriptor*@new: resource descriptor desired by caller* Returns 0 for success, conflict resource on error. |
reallocate_resource | allocate_resource - allocate a slot in the resource tree given range & alignment |
allocate_resource | allocate_resource - allocate empty slot in the resource tree given range & alignment |
__insert_resource | Insert a resource into the resource tree. If successful, return NULL,* otherwise return the conflicting resource (compare to __request_resource()) |
__reserve_region_with_split | |
__request_region | __request_region - create a new busy resource region*@parent: parent resource descriptor*@start: resource start address*@n: resource region size*@name: reserving caller's ID string*@flags: IO resource flags |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |