函数逻辑报告 |
Source Code:kernel\relay.c |
Create Date:2022-07-27 12:52:13 |
| Last Modify:2020-03-17 19:20:22 | Copyright©Brick |
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函数名称:lay_file_read_avail - boolean, are there unconsumed bytes available?
函数原型:static int relay_file_read_avail(struct rchan_buf *buf, size_t read_pos)
返回类型:int
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct rchan_buf * | buf | |
| size_t | read_pos |
| 996 | subbuf_size等于 sub-buffer size |
| 1011 | 如果此条件成立可能性小(为编译器优化)(produced - consumed >= n_subbufs)则 |
| 1014 | ytes consumed in cur read subbuf 等于0 |
| 1020 | 如果consumed大于produced则produced加等于n_subbufs乘subbuf_size |
| 1024 | 如果current offset into sub-buffer 恒等于subbuf_size且count of sub-buffers produced 大于count of sub-buffers consumed 则返回:1 |
| 1027 | 返回:0 |
| 1030 | 返回:1 |
| 名称 | 描述 |
|---|---|
| relay_file_read |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |