函数逻辑报告 |
Source Code:kernel\relay.c |
Create Date:2022-07-27 12:51:33 |
| Last Modify:2020-03-17 19:20:22 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:lay_create_buf - allocate and initialize a channel buffer*@chan: the relay channel* Returns channel buffer if successful, %NULL otherwise.
函数原型:static struct rchan_buf *relay_create_buf(struct rchan *chan)
返回类型:struct rchan_buf
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct rchan * | chan |
| 166 | 如果 number of sub-buffers per buffer 大于Maximum allocatable size 除*的长度则返回:NULL |
| 170 | 如果非buf则返回:NULL |
| 174 | 如果非padding counts per sub-buffer 则转到:free_buf |
| 178 | 如果非start of channel buffer 则转到:free_buf |
| 181 | associated channel 等于chan |
| 182 | 对象增加引用 |
| 183 | 返回:buf |
| 185 | free_buf : |
| 188 | 返回:NULL |
| 名称 | 描述 |
|---|---|
| relay_open_buf | lay_open_buf - create a new relay channel buffer* used by relay_open() and CPU hotplug. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |