函数逻辑报告 |
Source Code:kernel\rcu\tree.c |
Create Date:2022-07-27 11:27:44 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Compute the rcu_node tree geometry from kernel parameters. This cannot* replace the definitions in tree.h because those are needed to size* the ->node array in the rcu_state structure.
函数原型:static void __init rcu_init_geometry(void)
返回类型:void
参数:无
3477 | 如果jiffies_till_next_fqs恒等于ULONG_MAX则jiffies_till_next_fqs等于d |
3482 | 如果Increase (but not decrease) the RCU_FANOUT_LEAF at boot time. 恒等于RCU_FANOUT_LEAF且nr_cpu_ids恒等于CPU数量则返回 |
3485 | 打印信息("Adjusting geometry for rcu_fanout_leaf=%d, nr_cpu_ids=%u\n", Increase (but not decrease) the RCU_FANOUT_LEAF at boot time. , nr_cpu_ids) |
3494 | 如果Increase (but not decrease) the RCU_FANOUT_LEAF at boot time. 小于2或Increase (but not decrease) the RCU_FANOUT_LEAF at boot time. 大于sizeof(unsignedlong)乘8则 |
3497 | WARN_ON(1) |
3498 | 返回 |
3506 | 以i小于RCU_NUM_LVLS循环rcu_capacity[i]等于rcu_capacity[i - 1]乘RCU_FANOUT |
3513 | 如果nr_cpu_ids大于rcu_capacity[RCU_NUM_LVLS - 1]则 |
3515 | WARN_ON(1) |
3516 | 返回 |
3520 | 以nr_cpu_ids大于rcu_capacity[i]循环rcu_num_lvls等于i加1 |
3525 | 以i小于rcu_num_lvls循环 |
3526 | cap等于rcu_capacity[(rcu_num_lvls - 1) - i] |
3531 | rcu_num_nodes等于0 |
名称 | 描述 |
---|---|
rcu_init | 初始化直接读拷贝更新的锁机制 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |