函数逻辑报告 |
Source Code:kernel\rcu\rcutorture.c |
Create Date:2022-07-27 11:22:59 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Verify that double-free causes debug-objects to complain, but only* if CONFIG_DEBUG_OBJECTS_RCU_HEAD=y. Otherwise, say that the test* cannot be carried out.
函数原型:static void rcu_test_debug_objects(void)
返回类型:void
参数:无
| 2329 | 打印警报信息("%s: !CONFIG_DEBUG_OBJECTS_RCU_HEAD, not testing duplicate call_rcu()\n", KBUILD_MODNAME) |
| 名称 | 描述 |
|---|---|
| rcu_torture_init |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |