函数逻辑报告 |
Source Code:kernel\hung_task.c |
Create Date:2022-07-27 12:49:42 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Check whether a TASK_UNINTERRUPTIBLE does not get woken up for* a really long time (120 seconds). If that happens, print out* a warning.
函数原型:static void check_hung_uninterruptible_tasks(unsigned long timeout)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| unsigned long | timeout |
| 176 | last_break等于jiffies |
| 183 | 如果test_taint(TAINT_DIE)或did_panic则返回 |
| 186 | hung_task_show_lock = false |
| 194 | last_break等于jiffies |
| 197 | 如果任务状态恒等于深度睡眠态则check_hung_task(t, timeout) |
| 200 | unlock : |
| 204 | 如果hung_task_call_panic则 |
| 名称 | 描述 |
|---|---|
| watchdog | kthread which checks for tasks stuck in D state |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |