函数逻辑报告 |
Source Code:kernel\futex.c |
Create Date:2022-07-27 11:53:26 |
| Last Modify:2020-03-17 15:28:32 | Copyright©Brick |
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函数名称:Drop a reference to the resource addressed by a key.* The hash bucket spinlock must not be held. This is* a no-op for private futexes, see comment in the get* counterpart.
函数原型:static void drop_futex_key_refs(union futex_key *key)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| union futex_key * | key |
| 455 | 如果非ptr则 |
| 457 | WARN_ON_ONCE(1) |
| 458 | 返回 |
| 461 | 如果非IS_ENABLED(CONFIG_FOO) evaluates to 1 if CONFIG_FOO is set to 'y' or 'm',* 0 otherwise.(CONFIG_MMU)则返回 |
| 468 | 当: & == We set bit 1 if key has a reference on mm |
| 名称 | 描述 |
|---|---|
| put_futex_key | |
| futex_requeue | ex_requeue() - Requeue waiters from uaddr1 to uaddr2*@uaddr1: source futex user address*@flags: futex flags (FLAGS_SHARED, etc |
| unqueue_me | queue_me() - Remove the futex_q from its futex_hash_bucket*@q: The futex_q to unqueue* The q->lock_ptr must not be held by the caller |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |