函数逻辑报告 |
Source Code:kernel\auditsc.c |
Create Date:2022-07-27 12:29:47 |
| Last Modify:2020-03-17 16:31:21 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:match_tree_refs
函数原型:static int match_tree_refs(struct audit_context *ctx, struct audit_tree *tree)
返回类型:int
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct audit_context * | ctx | |
| struct audit_tree * | tree |
| 289 | 如果非tree则返回:0 |
| 298 | 如果p则 |
| 303 | 返回:0 |
| 名称 | 描述 |
|---|---|
| audit_filter_rules | Compare a task_struct with an audit_rule. Return 1 on match, 0* otherwise.* If task_creation is true, this is an explicit indication that we are* filtering a task rule at task creation time. This and tsk == current are |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |