函数逻辑报告 |
Source Code:kernel\audit_watch.c |
Create Date:2022-07-27 12:32:18 |
| Last Modify:2020-03-17 17:15:07 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:Find and return the audit_parent on the given inode. If found a reference* is taken on this parent.
函数原型:static inline struct audit_parent *audit_find_parent(struct inode *inode)
返回类型:struct audit_parent
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct inode * | inode |
| 90 | struct audit_parent * parent = NULL |
| 93 | entry等于Given a list of marks, find the mark associated with given group. If found* take a reference to that mark and return it, else return NULL. |
| 97 | 返回:parent |
| 名称 | 描述 |
|---|---|
| audit_add_watch | Find a matching watch entry, or add this one.* Caller must hold audit_filter_mutex. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |