函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:include\linux\list.h Create Date:2022-07-27 06:38:27
Last Modify:2020-03-12 14:18:49 Copyright©Brick
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函数名称:Check whether the node is the only node of the head without* accessing head:

函数原型:static inline bool hlist_is_singular_node(struct hlist_node *n, struct hlist_head *h)

返回类型:bool

参数:

类型参数名称
struct hlist_node *n
struct hlist_head *h
831  返回:非nextpprev恒等于first
调用者
名称描述
detach_if_pending