函数逻辑报告

Linux Kernel

v5.5.9

Brick Technologies Co., Ltd

Source Code:include\linux\ioport.h Create Date:2022-07-27 06:43:26
Last Modify:2020-03-12 14:18:49 Copyright©Brick
首页 函数Tree
注解内核,赢得工具下载SCCTEnglish

函数名称：True if any part of r1 overlaps r2

函数原型：static inline bool resource_overlaps(struct resource *r1, struct resource *r2)

返回类型：bool

参数：

类型参数名称
struct resource *r1
struct resource *r2
296  返回:start小于等于end且end大于等于start
调用者
名称描述
region_intersectsgion_intersects() - determine intersection of region with known resources*@start: region start address*@size: size of region*@flags: flags of resource (in iomem_resource)*@desc: descriptor of resource (in iomem_resource) or IORES_DESC_NONE* Check if the