函数逻辑报告 |
Source Code:include\linux\fscrypt.h |
Create Date:2022-07-29 10:32:14 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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注解内核,赢得工具 | 下载SCCT | English |
函数名称:scrypt_prepare_link - prepare to link an inode into a possibly-encrypted directory*@old_dentry: an existing dentry for the inode being linked*@dir: the target directory*@dentry: negative dentry for the target filename* A new link can only be added to an
函数原型:static inline int fscrypt_prepare_link(struct dentry *old_dentry, struct inode *dir, struct dentry *dentry)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct dentry * | old_dentry | |
struct inode * | dir | |
struct dentry * | dentry |
580 | 如果IS_ENCRYPTED(dir)则返回:__fscrypt_prepare_link(获得目录项的索引节点, dir, dentry) |
582 | 返回:0 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |