函数逻辑报告 |
Source Code:include\linux\fs_struct.h |
Create Date:2022-07-27 09:55:46 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:get_fs_root
函数原型:static inline void get_fs_root(struct fs_struct *fs, struct path *root)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct fs_struct * | fs | |
| struct path * | root |
| 29 | 加自旋锁 |
| 32 | 自旋锁解锁 |
| 名称 | 描述 |
|---|---|
| d_namespace_path | d_namespace_path - lookup a name associated with a given path*@path: path to lookup (NOT NULL)*@buf: buffer to store path to (NOT NULL)*@name: Returns - pointer for start of path name with in @buf (NOT NULL)*@flags: flags controlling path |
| set_root | |
| SYSCALL_DEFINE2 | pivot_root Semantics:* Moves the root file system of the current process to the directory put_old,* makes new_root as the new root file system of the current process, and sets* root/cwd of all processes which had them on the current root to new_root |
| current_chrooted | |
| mounts_open_common | |
| do_coredump |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |