函数逻辑报告 |
Source Code:include\linux\capability.h |
Create Date:2022-07-27 06:41:17 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:cap_isclear
函数原型:static inline bool cap_isclear(const kernel_cap_t a)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
const kernel_cap_t | a |
156 | 返回:true |
名称 | 描述 |
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audit_log_cap | |
cap_issubset | Check if "a" is a subset of "set".* return true if ALL of the capabilities in "a" are also in "set"* cap_issubset(0101, 1111) will return true* return false if ANY of the capabilities in "a" are not in "set"* cap_issubset(1111, 0101) will return false |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |