函数逻辑报告

函数名称：map_from_u64 - Check and swap words within u64.*@mask: source bitmap*@dst: destination bitmap* In 32-bit Big Endian kernel, when using ``(u32 *)(&val)[*]``* to read u64 mask, we will get the wrong word.* That is ``(u32 *)(&val)[0]`` gets the upper 32 bits,

函数原型：static inline void bitmap_from_u64(unsigned long *dst, u64 mask)

返回类型：void

参数：