may_umount

函数名称：may_umount_tree - check if a mount tree is busy*@mnt: root of mount tree* This is called to check if a tree of mounts has any* open files, pwds, chroots or sub mounts that are* busy.

函数原型：int may_umount_tree(struct vfsmount *m)

返回类型：int

参数：

类型	参数	名称
struct vfsmount *	m

1309

mnt等于real_mount(m)

1310

actual_refs等于0

1311

minimum_refs等于0

1313

BUG_ON(!m)

1316

lock_mount_hash()

1317

以p 循环

1318

actual_refs加等于vfsmount lock must be held for write

1319

minimum_refs加等于2

1321

unlock_mount_hash()

1323

如果actual_refs大于minimum_refs则返回:0

1326

返回:1

源代码转换工具开放的插件接口	X
支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告代码生成和批量转换代码

函数逻辑报告