函数逻辑报告 |
Source Code:fs\namespace.c |
Create Date:2022-07-29 10:39:31 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:may_umount - check if a mount point is busy*@mnt: root of mount* This is called to check if a mount point has any* open files, pwds, chroots or sub mounts. If the* mount has sub mounts this will return busy* regardless of whether the sub mounts are busy.
函数原型:int may_umount(struct vfsmount *mnt)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct vfsmount * | mnt |
1346 | ret等于1 |
1347 | lock for reading |
1348 | lock_mount_hash() |
1351 | unlock_mount_hash() |
1352 | lease a read lock |
1353 | 返回:ret |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |