函数逻辑报告 |
Source Code:fs\namespace.c |
Create Date:2022-07-29 10:39:39 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:Check that there aren't references to earlier/same mount namespaces in the* specified subtree. Such references can act as pins for mount namespaces* that aren't checked by the mount-cycle checking code, thereby allowing* cycles to be made.
函数原型:static bool check_for_nsfs_mounts(struct mount *subtree)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct mount * | subtree |
2585 | bool ret = false |
2587 | lock_mount_hash() |
2588 | 以p循环如果mnt_ns_loop( root of the mounted tree )则 |
2590 | 转到:out |
2592 | ret = true |
2593 | out : |
2594 | unlock_mount_hash() |
2595 | 返回:ret |
名称 | 描述 |
---|---|
do_move_mount |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |