step_into

函数名称：Do we need to follow links? We _really_ want to be able* to do this check without having to look at inode->i_op,* so we keep a cache of "no, this doesn't need follow_link"* for the common case.

函数原型：static inline int step_into(struct nameidata *nd, struct path *path, int flags, struct inode *inode, unsigned seq)

返回类型：int

参数：

类型	参数	名称
struct nameidata *	nd
struct path *	path
int	flags
struct inode *	inode
unsigned	seq

1763

如果非flags按位与WALK_MORE的值且depth则put_link(nd)

1765

如果此条件成立可能性大(为编译器优化)(!d_is_symlink(dentry))或非flags按位与WALK_FOLLOW或flags按位与llow links at the end 的值则

1768

path_to_nameidata(path, nd)

1769

path.dentry.d_inode 等于inode

1770

seq等于seq

1771

返回:0

1774

如果flags按位与RCU pathwalk mode; semi-internal 则

1775

如果ad_seqcount_retry - end a seq-read critical section*@s: pointer to seqcount_t*@start: count, from read_seqcount_begin* Returns: 1 if retry is required, else 0* read_seqcount_retry closes a read critical section of the given seqcount则返回:负ECHILD

1778

返回:pick_link(nd, path, inode, seq)

**调用者**
名称	描述
walk_component
do_last	Handle the last step of open()

源代码转换工具开放的插件接口	X
支持：c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现：逻辑报告代码生成和批量转换代码

函数逻辑报告