函数逻辑报告 |
Source Code:fs\io_uring.c |
Create Date:2022-07-29 10:54:34 |
| Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
| 首页 | 函数Tree |
| 注解内核,赢得工具 | 下载SCCT | English |
函数名称:io_req_find_next
函数原型:static void io_req_find_next(struct io_kiocb *req, struct io_kiocb **nxt)
返回类型:void
参数:
| 类型 | 参数 | 名称 |
|---|---|---|
| struct io_kiocb * | req | |
| struct io_kiocb ** | nxt |
| 1055 | 如果此条件成立可能性大(为编译器优化)(!(flags & linked sqes ))则返回 |
| 1064 | 如果flags按位与ail rest of links 则 |
| 1066 | 否则如果flags按位与has linked timeout 按位或completion under lock 的值的值恒等于has linked timeout 则 |
| 1076 | spin_lock_irqsave( & completion_lock, flags) |
| 1077 | io_req_link_next(req, nxt) |
| 1078 | spin_unlock_irqrestore( & completion_lock, flags) |
| 1079 | 否则 |
| 1080 | io_req_link_next(req, nxt) |
| 名称 | 描述 |
|---|---|
| io_free_req | |
| io_put_req_find_next | Drop reference to request, return next in chain (if there is one) if this* was the last reference to this request. |
| 源代码转换工具 开放的插件接口 | X |
|---|---|
| 支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |