函数逻辑报告 |
Source Code:fs\dcache.c |
Create Date:2022-07-29 10:37:36 |
Last Modify:2020-03-18 10:27:32 | Copyright©Brick |
首页 | 函数Tree |
注解内核,赢得工具 | 下载SCCT | English |
函数名称:是子目录
函数原型:bool is_subdir(struct dentry *new_dentry, struct dentry *old_dentry)
返回类型:bool
参数:
类型 | 参数 | 名称 |
---|---|---|
struct dentry * | new_dentry | |
struct dentry * | old_dentry |
3072 | 如果new_dentry恒等于old_dentry则返回:true |
3075 | 循环 |
3083 | 如果d_ancestor - search for an ancestor*@p1: ancestor dentry*@p2: child dentry* Returns the ancestor dentry of p2 which is a child of p1, if p1 is* an ancestor of p2, else NULL.则result = true |
3085 | 否则result = false |
3088 | 当read_seqretry( & rename_lock, seq)循环 |
3090 | 返回:result |
名称 | 描述 |
---|---|
copy_tree | |
has_locked_children | |
is_path_reachable | Return true if path is reachable from root* namespace_sem or mount_lock is held |
propagate_one |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |