函数逻辑报告 |
Source Code:fs\crypto\policy.c |
Create Date:2022-07-29 10:57:52 |
Last Modify:2020-03-12 14:18:49 | Copyright©Brick |
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函数名称:scrypt_has_permitted_context() - is a file's encryption policy permitted* within its directory?*@parent: inode for parent directory*@child: inode for file being looked up, opened, or linked into @parent* Filesystems must call this before permitting access
函数原型:int fscrypt_has_permitted_context(struct inode *parent, struct inode *child)
返回类型:int
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | parent | |
struct inode * | child |
458 | 如果非IS_ENCRYPTED(parent)则返回:1 |
462 | 如果非IS_ENCRYPTED(child)则返回:0 |
481 | 如果err则返回:0 |
484 | 如果err则返回:0 |
487 | err等于fscrypt_get_policy(parent, & parent_policy) |
488 | 如果err则返回:0 |
491 | err等于fscrypt_get_policy(child, & child_policy) |
492 | 如果err则返回:0 |
源代码转换工具 开放的插件接口 | X |
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支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |