函数逻辑报告 |
Source Code:fs\buffer.c |
Create Date:2022-07-29 10:45:10 |
Last Modify:2020-03-18 10:38:29 | Copyright©Brick |
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函数名称:Invalidate any and all dirty buffers on a given inode. We are* probably unmounting the fs, but that doesn't mean we have already* done a sync(). Just drop the buffers from the inode list.* NOTE: we take the inode's blockdev's mapping's private_lock. Which
函数原型:void invalidate_inode_buffers(struct inode *inode)
返回类型:void
参数:
类型 | 参数 | 名称 |
---|---|---|
struct inode * | inode |
803 | 如果inode_has_buffers(inode)则 |
名称 | 描述 |
---|---|
bdev_evict_inode |
源代码转换工具 开放的插件接口 | X |
---|---|
支持:c/c++/esqlc/java Oracle/Informix/Mysql 插件可实现:逻辑报告 代码生成和批量转换代码 |